Q 12-03-162JEE MainJEE Main 2022 (25 Jun, Shift 1)Medium
The total current supplied to the circuit as shown in figure by the $5\ \text{V}$ battery is ______ A.
Numerical value type. Enter your answer.
Answer: 2
The wire loop makes the contact points of the two $5\ \Omega$ spokes the same node as one battery terminal (call it $P$). The other battery terminal is joined by wire to the $2.5\ \Omega$ spoke (node $Q$), and the $5\ \Omega$ resistor on the loop lies directly between $P$ and $Q$.
Between $P$ and the centre: $5\parallel5 = 2.5\ \Omega$; from the centre to $Q$: $2.5\ \Omega$. This path ($5\ \Omega$) is in parallel with the $5\ \Omega$ on the loop:
$$R_{eq} = \frac{5\times5}{10} = 2.5\ \Omega,\qquad I = \frac{5}{2.5} = 2\ \text{A}$$
Solution by Sreeraj P, M.Sc Physics