Q 12-03-127JEE MainJEE Main 2023 (24 Jan, Shift 2)Easy
A cell of emf $90\ \text{V}$ is connected across series combination of two resistors each of $100\ \Omega$ resistance. A voltmeter of resistance $400\ \Omega$ is used to measure the potential difference across each resistor. The reading of the voltmeter will be
Answer: (A) $40\ \text{V}$
Voltmeter across one resistor: $100\parallel400=80\ \Omega$, in series with $100\ \Omega$.
$$V=90\times\frac{80}{180}=40\ \text{V}$$
Solution by Sreeraj P, M.Sc Physics