Q 12-12-085JEE MainJEE Main 2022 (25 Jul, Shift 1)Easy
The momentum of an electron revolving in the $n^{\text{th}}$ orbit is given by: (Symbols have their usual meanings)
Answer: (A) $\dfrac{nh}{2\pi r}$
Bohr's quantisation: $mvr = \dfrac{nh}{2\pi}\Rightarrow p = mv = \dfrac{nh}{2\pi r}$.
Solution by Sreeraj P, M.Sc Physics