Q 12-12-075JEE MainJEE Main 2023 (6 Apr, Shift 1)Easy
The radius of fifth orbit of $\text{Li}^{++}$ is ______ $\times10^{-12}$ m. Take: radius of hydrogen atom $=0.51\ \text{Å}$
Numerical value type. Enter your answer.
Answer: 425
$r=r_0\dfrac{n^2}{Z}=0.51\times\dfrac{25}{3}=4.25\ \text{Å}=425\times10^{-12}\ \text{m}$.
Solution by Sreeraj P, M.Sc Physics