Atoms question for JEE Main (JEE Main 2023 (1 Feb, Shift 2)), with solution

An electron of a hydrogen like atom, having $Z=4$, jumps from $4^\text{th}$ energy state to $2^\text{nd}$ energy state. The energy released in this process will be (Given $Rch=13.6$ eV, where $R$ = Rydberg constant, $c$ = speed of light in vacuum, $h$ = Planck's constant)