Q 12-12-026JEE MainMedium
Find the shortest wavelength, in nm, in the Lyman series of hydrogen. ($R = 1.097 \times 10^7\ \text{m}^{-1}$; give the nearest whole number)
Numerical value type. Enter your answer.
Answer: 91
Concept. The shortest Lyman wavelength is the series limit, $n = \infty \to 1$: $\dfrac{1}{\lambda} = R$.
Step 1. Substitute.
$$\lambda = \frac{1}{1.097 \times 10^7} = 9.12 \times 10^{-8}\ \text{m} \approx 91\ \text{nm}$$
Answer. $91$.
Solution by Sreeraj P, M.Sc Physics