Q 12-12-026JEE MainMedium
Find the shortest wavelength, in nm, in the Lyman series of hydrogen. ($R = 1.097 \times 10^7\ \text{m}^{-1}$; give the nearest whole number)
Numerical value type. Enter your answer.
Answer: 91
Series limit ($n = \infty \to 1$): $\lambda = \dfrac{1}{R} = 9.12 \times 10^{-8}$ m $\approx 91$ nm.
Solution by Sreeraj P, M.Sc Physics