Q 12-12-030JEE MainJEE Main 2026 (2 Apr, Shift 1)Easy
Angular momentum of an electron in a hydrogen atom is $\dfrac{3h}{\pi}$, then the energy of the electron is ______ eV.
Answer: (C) $-0.38$
Bohr's rule: $L=\dfrac{nh}{2\pi}=\dfrac{3h}{\pi}=\dfrac{6h}{2\pi}$, so $n=6$.
$$E_6=-\frac{13.6}{6^2}=-\frac{13.6}{36}\approx-0.38\ \text{eV}$$
Solution by Sreeraj P, M.Sc Physics