Q 12-12-023NEETJEE MainTop questionMedium
The energy of the electron in the ground state of hydrogen is $-13.6$ eV. The energy required to excite it from the ground state to the second excited state is
Answer: (D) $12.09$ eV
Concept. The second excited state is $n = 3$; the energy needed is $E_3 - E_1$ with $E_n = -\dfrac{13.6}{n^2}$ eV.
Step 1. Energy of $n = 3$. $E_3 = -\dfrac{13.6}{9} = -1.51$ eV.
Step 2. Excitation energy. $E_3 - E_1 = -1.51 + 13.6 = 12.09$ eV.
Answer. $12.09$ eV (Option D).
Solution by Sreeraj P, M.Sc Physics