Q 12-12-012NEETJEE MainEasy
The total energy of the electron in the $n = 3$ orbit of hydrogen is
Answer: (A) $-1.51$ eV
$E_n = -\dfrac{13.6}{n^2}$ eV $= -\dfrac{13.6}{9} \approx -1.51$ eV.
Solution by Sreeraj P, M.Sc Physics
The total energy of the electron in the $n = 3$ orbit of hydrogen is
Answer: (A) $-1.51$ eV
$E_n = -\dfrac{13.6}{n^2}$ eV $= -\dfrac{13.6}{9} \approx -1.51$ eV.
Solution by Sreeraj P, M.Sc Physics