Q 12-07-152NEETNEET 2022Top questionEasy
The peak voltage of the ac source is equal to
Answer: (D) $\sqrt{2}$ times the rms value of the ac source
For a sinusoidal voltage $V_{rms} = \dfrac{V_0}{\sqrt{2}}$, so $V_0 = \sqrt{2}\,V_{rms}$.
Solution by Sreeraj P, M.Sc Physics