Q 12-07-143JEE MainJEE Main 2019 (10 Apr, Shift 1)Easy
A transformer consisting of $300$ turns in the primary and $150$ turns in the secondary gives output power of $2.2\ \text{kW}$. If the current in the secondary coil is $10\ \text{A}$, then the input voltage and current in the primary coil are:
Answer: (C) $440\ \text{V}$ and $5\ \text{A}$
Secondary voltage $= \dfrac{2200}{10} = 220\ \text{V}$. Primary voltage $= 220\times\dfrac{300}{150} = 440\ \text{V}$.
For an ideal transformer, $I_p = \dfrac{2200}{440} = 5\ \text{A}$.
Solution by Sreeraj P, M.Sc Physics