Q 12-07-079JEE MainJEE Main 2023 (25 Jan, Shift 1)Easy
An LCR series circuit of capacitance $62.5\ \text{nF}$ and resistance of $50\ \Omega$ is connected to an A.C. source of frequency $2.0\ \text{kHz}$. For maximum value of amplitude of current in circuit, the value of inductance is ______ mH. (Take $\pi^2=10$)
Numerical value type. Enter your answer.
Answer: 100
Resonance: $L=\dfrac{1}{4\pi^2f^2C}=\dfrac{1}{40\times4\times10^6\times62.5\times10^{-9}}=\dfrac{1}{10}\ \text{H}=100\ \text{mH}$.
Solution by Sreeraj P, M.Sc Physics