Q 12-07-085JEE MainJEE Main 2023 (6 Apr, Shift 2)Easy
A capacitor of capacitance $150.0\ \mu\text{F}$ is connected to an alternating source of emf given by $E=36\sin(120\pi t)$ V. The maximum value of current in the circuit is approximately equal to
Answer: (A) $2\ \text{A}$
$I_0=E_0\omega C=36\times120\pi\times150\times10^{-6}\approx2.04\ \text{A}\approx2\ \text{A}$.
Solution by Sreeraj P, M.Sc Physics