Q 12-07-023NEETJEE MainMedium
A $2\ \mu$F capacitor is to resonate with an inductor at $1000/\pi$ Hz. The inductance required is
Answer: (B) $0.125$ H
Concept. Resonance: $L = \dfrac{1}{\omega^2C}$.
Step 1. Angular frequency. $\omega = 2\pi \times \dfrac{1000}{\pi} = 2000$ rad/s.
Step 2. Inductance.
$$L = \frac{1}{4 \times 10^6 \times 2 \times 10^{-6}} = 0.125\ \text{H}$$
Answer. $0.125$ H (Option B).
Solution by Sreeraj P, M.Sc Physics