Q 12-07-028NEETJEE MainMedium
A transformer of efficiency $90\%$ steps $220$ V down to $22$ V and delivers $198$ W to a load. The current in the primary is
Answer: (C) $1$ A
Input power $= \dfrac{198}{0.9} = 220$ W, so $I_p = \dfrac{220}{220} = 1$ A.
Solution by Sreeraj P, M.Sc Physics