Q 11-05-019NEETEAMCET 2013 (Medical)Easy
A body of mass $300$ kg is moved through $10$ m along a smooth inclined plane of inclination $30°$. The work done in moving it (in joules) is ($g = 9.8\ \text{m s}^{-2}$)
Answer: (C) $14700$
On a smooth plane the work done equals the gain in potential energy. Height gained $= 10\sin 30° = 5$ m:
$$W = mgh = 300 \times 9.8 \times 5 = 14700\ \text{J}$$
Solution by Sreeraj P, M.Sc Physics