Q 11-05-019NEETEAMCET 2013 (Medical)Easy
A body of mass $300$ kg is moved through $10$ m along a smooth inclined plane of inclination $30°$. The work done in moving it (in joules) is ($g = 9.8\ \text{m s}^{-2}$)
Answer: (C) $14700$
Concept. On a smooth plane the work equals the gain in PE.
Step 1. Height. $10\sin30° = 5$ m.
Step 2. Work. $300 \times 9.8 \times 5 = 14700$ J.
Answer. $14700$ (Option C).
Solution by Sreeraj P, M.Sc Physics