Q 11-14-138NEETNEET 2022Top questionEasy
If the initial tension on a stretched string is doubled, then the ratio of the initial and final speeds of a transverse wave along the string is
Answer: (D) $1 : \sqrt{2}$
Speed of a transverse wave on a string: $v = \sqrt{\dfrac{T}{\mu}}$, so $v \propto \sqrt{T}$ for the same string.
$$\frac{v_1}{v_2} = \sqrt{\frac{T}{2T}} = \frac{1}{\sqrt{2}}$$
Solution by Sreeraj P, M.Sc Physics