Q 11-14-019NEETJEE MainMedium
In a resonance tube experiment with a $512$ Hz fork, the first and second resonances occur at air-column lengths of $16$ cm and $49$ cm. The speed of sound in air is
Answer: (C) $337.9$ m/s
Successive resonances are $\dfrac{\lambda}{2}$ apart: $\dfrac{\lambda}{2} = 33$ cm, so $\lambda = 0.66$ m and $v = 512 \times 0.66 \approx 337.9$ m/s. (Using the difference removes the end correction.)
Solution by Sreeraj P, M.Sc Physics