Q 12-10-139JEE MainJEE Main 2019 (8 Apr, Shift 1)Easy
In an interference experiment the ratio of amplitudes of coherent waves is $\dfrac{a_1}{a_2} = \dfrac13$. The ratio of maximum and minimum intensities of fringes will be
Answer: (A) $4$
$$\frac{I_{\max}}{I_{\min}} = \left(\frac{a_1 + a_2}{a_2 - a_1}\right)^2 = \left(\frac{1 + 3}{3 - 1}\right)^2 = 4$$
Solution by Sreeraj P, M.Sc Physics