Q 12-10-101JEE MainJEE Main 2022 (27 Jul, Shift 1)Easy
A microscope was initially placed in air (refractive index $1$). It is then immersed in oil (refractive index $2$). For a light whose wavelength in air is $\lambda$, calculate the change of microscope's resolving power due to oil and choose the correct option
Answer: (B) Resolving power will be twice in the oil than it was in the air.
The resolving power of a microscope is $\dfrac{2n\sin\theta}{1.22\lambda}$, proportional to the refractive index $n$ of the medium.
Going from $n = 1$ to $n = 2$ doubles the resolving power.
Solution by Sreeraj P, M.Sc Physics