Match List-I with List-II.
$$\begin{array}{|l|l|l|l|}\hline & \text{List-I} & & \text{List-II} \\ \hline \text{A.} & \text{Boltzmann constant} & \text{I.} & ML^2T^{-1} \\ \hline \text{B.} & \text{Coefficient of viscosity} & \text{II.} & MLT^{-3}K^{-1} \\ \hline \text{C.} & \text{Planck's constant} & \text{III.} & ML^2T^{-2}K^{-1} \\ \hline \text{D.} & \text{Thermal conductivity} & \text{IV.} & ML^{-1}T^{-1} \\ \hline \end{array}$$
Choose the correct answer from the options given below:
Answer: (A) A-III, B-IV, C-I, D-II
- A. $k_B = \dfrac{\text{energy}}{\text{temperature}}$: $ML^2T^{-2}K^{-1}$ → III
- B. $\eta = \dfrac{F}{6\pi rv}$: $\dfrac{MLT^{-2}}{L\cdot LT^{-1}} = ML^{-1}T^{-1}$ → IV
- C. $h = \dfrac{E}{\nu}$: $ML^2T^{-1}$ → I
- D. From $\dfrac{dQ}{dt} = KA\dfrac{dT}{dx}$: $K = \dfrac{ML^2T^{-3}\cdot L}{L^2\cdot K} = MLT^{-3}K^{-1}$ → II
Solution by Sreeraj P, M.Sc Physics