Q 11-01-204JEE MainJEE Main 2020 (2 Sep, Shift 1)Easy
If speed $V$, area $A$ and force $F$ are chosen as fundamental units, then the dimension of Young's modulus will be
Answer: (D) $FA^{-1}V^{0}$
Young's modulus is stress divided by strain, and strain is dimensionless, so $Y$ has the dimensions of force per unit area:
$$Y = \frac{F}{A} = F A^{-1} V^{0}$$
Solution by Sreeraj P, M.Sc Physics