Q 11-01-182JEE MainJEE Main 2021 (20 Jul, Shift 2)Medium
If time $(t)$, velocity $(v)$, and angular momentum $(l)$ are taken as the fundamental units. Then the dimension of mass $(m)$ in terms of $t$, $v$ and $l$ is:
Answer: (D) $[t^{-1}v^{-2}l^1]$
$[l] = [\text{ML}^2\text{T}^{-1}]$, and length $= vt$, so $[l] = [\text{M}][v^2t^2][t^{-1}] = [\text{M}v^2t]$.
$[m] = [t^{-1}v^{-2}l^1]$.
Solution by Sreeraj P, M.Sc Physics