Units and Measurements question for JEE Main (JEE Main 2024 (9 Apr, Shift 1)), with solution

Answer: (B) $[\text{M}^0\text{L}^2\text{T}^{-2}]$

Latent heat is energy per unit mass:
$$[L] = \frac{[\text{ML}^2\text{T}^{-2}]}{[\text{M}]} = [\text{M}^0\text{L}^2\text{T}^{-2}]$$

Solution by Sreeraj P, M.Sc Physics