Q 11-01-098JEE MainJEE Main 2024 (5 Apr, Shift 2)Easy
A vernier calliper has 20 divisions on the vernier scale, which coincide with the $19^{\text{th}}$ division on the main scale. The least count of the instrument is $0.1\ \text{mm}$. One main scale division is equal to ______ mm.
Answer: (B) $2$
$20\ \text{VSD} = 19\ \text{MSD} \Rightarrow \text{LC} = 1\ \text{MSD} - 1\ \text{VSD} = \dfrac{1}{20}\ \text{MSD}$.
$$\frac{\text{MSD}}{20} = 0.1\ \text{mm} \Rightarrow \text{MSD} = 2\ \text{mm}$$
Solution by Sreeraj P, M.Sc Physics