Q 11-11-031NEETJEE MainMedium
One mole of an ideal gas does $W$ of work in an isobaric expansion. The heat absorbed is ($\gamma$ = ratio of specific heats)
Answer: (B) $\dfrac{\gamma W}{\gamma - 1}$
Concept. Isobaric: $W = nR\Delta T$, $Q = nC_P\Delta T$ with $C_P = \dfrac{\gamma R}{\gamma - 1}$.
Step 1. Ratio. $Q = \dfrac{\gamma W}{\gamma - 1}$.
Answer. $\dfrac{\gamma W}{\gamma - 1}$ (Option B).
Solution by Sreeraj P, M.Sc Physics