Q 11-06-009NEETNEET 2024Top questionEasy
The moment of inertia of a thin rod about an axis passing through its mid point and perpendicular to the rod is $2400\ \text{g cm}^2$. The length of the $400$ g rod is nearly :
Answer: (C) $8.5$ cm
$$I = \frac{ML^2}{12} \;\Rightarrow\; L^2 = \frac{12I}{M} = \frac{12 \times 2400}{400} = 72\ \text{cm}^2$$
$$L = \sqrt{72} \approx 8.5\ \text{cm}$$
Solution by Sreeraj P, M.Sc Physics