Q 12-14-211JEE MainJEE Main 2025 (3 Apr, Shift 2)Easy
The truth table corresponding to the circuit given below is:
Answer: (B) $\begin{array}{c|c|c}A & B & C\\ \hline 0&0&0\\ 0&1&0\\ 1&0&1\\ 1&1&1\end{array}$
The OR gate gives $A + B$, and the AND gate combines it with $A$:
$$C = A\cdot(A + B) = A$$
So $C$ simply follows $A$: $C = 0, 0, 1, 1$ for $(A, B) = (0,0), (0,1), (1,0), (1,1)$. This is table (2).
Solution by Sreeraj P, M.Sc Physics