Semiconductor Electronics question for JEE Main (JEE Main 2024 (31 Jan, Shift 2)), with solution

Answer: (C) $\begin{array}{cc|c} A & B & Y \\ \hline 0 & 0 & 0 \\ 1 & 0 & 0 \\ 0 & 1 & 0 \\ 1 & 1 & 0\end{array}$

The upper OR gate gives $A + \bar B$ and the lower one gives $\bar A + B$. The NOR gate gives
$$Y = \overline{(A + \bar B) + (\bar A + B)} = \overline{(A + \bar A) + (B + \bar B)} = \overline{1} = 0$$
So $Y = 0$ for every input combination.

Solution by Sreeraj P, M.Sc Physics