Q 12-14-058JEE MainJEE Main 2025 (29 Jan, Shift 2)Medium
The truth table for the circuit given below is
Answer: (D) $\begin{array}{|c|c|c|}\hline A & B & Y \\ \hline 0 & 0 & 0 \\ \hline 0 & 1 & 1 \\ \hline 1 & 0 & 1 \\ \hline 1 & 1 & 0 \\ \hline\end{array}$
- Upper AND gate: $A$ and $\bar B$, output $A\bar B$.
- Lower AND gate: $\bar A$ and $B$, output $\bar AB$.
- OR gate: $Y = A\bar B + \bar AB$, the XOR function.
$Y = 1$ only when exactly one input is 1: $00 \to 0$, $01 \to 1$, $10 \to 1$, $11 \to 0$. Table (4).
Solution by Sreeraj P, M.Sc Physics