Q 12-09-116JEE MainJEE Main 2023 (11 Apr, Shift 1)Easy
The critical angle for a denser–rarer interface is $45^\circ$. The speed of light in rarer medium is $3\times10^8\ \text{m s}^{-1}$. The speed of light in the denser medium is
Answer: (C) $2.12\times10^8\ \text{m s}^{-1}$
$\sin C=\dfrac{v_d}{v_r}\Rightarrow v_d=3\times10^8\times\dfrac1{\sqrt2}=2.12\times10^8\ \text{m s}^{-1}$.
Solution by Sreeraj P, M.Sc Physics