Q 12-09-095JEE MainJEE Main 2024 (8 Apr, Shift 1)Easy
Critical angle of incidence for a pair of optical media is $45^\circ$. The refractive indices of first and second media are in the ratio:
Answer: (B) $\sqrt2:1$
Light goes from the denser (first) medium to the rarer (second):
$$\sin C = \frac{\mu_2}{\mu_1} = \sin45^\circ = \frac{1}{\sqrt2} \;\Rightarrow\; \mu_1 : \mu_2 = \sqrt2 : 1$$
Solution by Sreeraj P, M.Sc Physics