Q 12-13-137NEETNEET 2022Top questionEasy
In the given nuclear reaction, the element $X$ is
$$^{22}_{11}\text{Na} \rightarrow X + e^+ + \nu$$
Answer: (D) $^{22}_{10}\text{Ne}$
In $\beta^+$ decay a proton turns into a neutron, emitting a positron and a neutrino. The mass number stays the same and the atomic number drops by 1.
Charge: $11 = Z + 1 \Rightarrow Z = 10$. Mass number: $A = 22$.
$X$ is $^{22}_{10}\text{Ne}$.
Solution by Sreeraj P, M.Sc Physics