Q 12-04-067JEE MainJEE Main 2024 (1 Feb, Shift 2)Easy
In an ammeter, $5\%$ of the main current passes through the galvanometer. If the resistance of the galvanometer is $G$, the resistance of the ammeter will be
Answer: (A) $\dfrac{G}{20}$
The galvanometer and shunt are in parallel: $0.05I\cdot G = 0.95I\cdot S \Rightarrow S = \dfrac{G}{19}$.
$$R_A = \frac{GS}{G + S} = \frac{G\cdot G/19}{20G/19} = \frac{G}{20}$$
Solution by Sreeraj P, M.Sc Physics