Q 12-04-031NEETJEE MainMedium
A galvanometer of resistance $50\ \Omega$ gives full-scale deflection for $5$ mA. To use it as an ammeter of range $0$–$5$ A, the resistance to connect is about
Answer: (C) $0.05\ \Omega$ in parallel
The shunt must carry the rest of the current, $5 - 0.005 = 4.995$ A, at the same voltage as the galvanometer:
$$S = \frac{I_g G}{I - I_g} = \frac{0.005 \times 50}{4.995} \approx 0.05\ \Omega$$
A shunt is connected in parallel.
Solution by Sreeraj P, M.Sc Physics