Motion in a Plane question for JEE Main (JEE Main 2020 (8 Jan, Shift 1)), with solution

A particle is moving along the $x$-axis with its coordinate with time $t$ given by $x(t) = 10 + 8t - 3t^2$. Another particle is moving along the $y$-axis with its coordinate as a function of time given by $y(t) = 5 - 8t^3$. At $t = 1$ s, the speed of the second particle as measured in the frame of the first particle is given as $\sqrt v$. Then $v$ (in m s$^{-1}$) is ______.