Q 12-05-075JEE MainJEE Main 2019 (11 Jan, Shift 2)Easy
A paramagnetic substance in the form of a cube with sides $1$ cm has a magnetic dipole moment of $20\times10^{-6}$ J/T when a magnetic intensity of $60\times10^{3}$ A/m is applied. Its magnetic susceptibility is:
Answer: (D) $3.3\times10^{-4}$
Magnetisation $M = \dfrac{m}{V} = \dfrac{20\times10^{-6}}{10^{-6}} = 20$ A/m.
$$\chi = \frac MH = \frac{20}{60\times10^3} \approx 3.3\times10^{-4}$$
Solution by Sreeraj P, M.Sc Physics