Match List - I with List - II:
$$\begin{array}{|l|l|l|l|}\hline & \text{List - I} & & \text{List - II} \\ \hline \text{a} & \text{Magnetic induction} & \text{i} & \text{ML}^2\text{T}^{-2}\text{A}^{-1} \\ \hline \text{b} & \text{Magnetic flux} & \text{ii} & \text{M}^0\text{L}^{-1}\text{A} \\ \hline \text{c} & \text{Magnetic permeability} & \text{iii} & \text{MT}^{-2}\text{A}^{-1} \\ \hline \text{d} & \text{Magnetization} & \text{iv} & \text{MLT}^{-2}\text{A}^{-2} \\ \hline \end{array}$$
Choose the most appropriate answer from the options given below:
Answer: (B) (a) − (iii), (b) − (i), (c) − (iv), (d) − (ii)
- Magnetic induction: $F = qvB \Rightarrow [B] = \dfrac{\text{MLT}^{-2}}{\text{AT}\cdot\text{LT}^{-1}} = \text{MT}^{-2}\text{A}^{-1}$ (iii)
- Magnetic flux $= BA$: $\text{ML}^2\text{T}^{-2}\text{A}^{-1}$ (i)
- Permeability: $B = \dfrac{\mu_0 I}{2\pi r} \Rightarrow [\mu_0] = \text{MLT}^{-2}\text{A}^{-2}$ (iv)
- Magnetization (magnetic moment per volume): $\dfrac{\text{AL}^2}{\text{L}^3} = \text{M}^0\text{L}^{-1}\text{A}$ (ii)
Solution by Sreeraj P, M.Sc Physics