Q 12-05-049JEE MainJEE Main 2022 (27 Jun, Shift 1)Easy
The susceptibility of a paramagnetic material is $99$. The permeability of the material in Wb/A-m, is [Permeability of free space $\mu_0 = 4\pi\times10^{-7}$ Wb/A-m]
Answer: (A) $4\pi\times10^{-5}$
$$\mu = \mu_0(1 + \chi) = 4\pi\times10^{-7}\times(1 + 99) = 4\pi\times10^{-5}\ \text{Wb/A-m}$$
Solution by Sreeraj P, M.Sc Physics