Match List-I with List-II.
$$\begin{array}{|l|l|l|l|}\hline & \text{List-I} & & \text{List-II} \\ \hline \text{A.} & \text{Triatomic rigid gas} & \text{I.} & C_P/C_V = 5/3 \\ \hline \text{B.} & \text{Diatomic non-rigid gas} & \text{II.} & C_P/C_V = 7/5 \\ \hline \text{C.} & \text{Monoatomic gas} & \text{III.} & C_P/C_V = 4/3 \\ \hline \text{D.} & \text{Diatomic rigid gas} & \text{IV.} & C_P/C_V = 9/7 \\ \hline \end{array}$$
Choose the correct answer from the options given below:
Answer: (A) A-III, B-IV, C-I, D-II
$\gamma = 1 + \dfrac2f$, where $f$ is the number of degrees of freedom.
- A. Triatomic rigid (non-linear): $f = 6$, $\gamma = \tfrac43$ → III
- B. Diatomic non-rigid (one vibrational mode adds 2): $f = 7$, $\gamma = \tfrac97$ → IV
- C. Monoatomic: $f = 3$, $\gamma = \tfrac53$ → I
- D. Diatomic rigid: $f = 5$, $\gamma = \tfrac75$ → II
Solution by Sreeraj P, M.Sc Physics