Q 11-12-147JEE MainJEE Main 2019 (12 Jan, Shift 1)Easy
An ideal gas occupies a volume of $2\ \text{m}^3$ at a pressure of $3\times10^{6}$ Pa. The energy of the gas is:
Answer: (B) $9\times10^{6}$ J
The (translational kinetic) energy of an ideal gas is
$$E = \frac32PV = \frac32\times3\times10^6\times2 = 9\times10^{6}\ \text{J}$$
Solution by Sreeraj P, M.Sc Physics