Q 12-02-158JEE MainJEE Main 2020 (3 Sep, Shift 1)Easy
In the circuit shown in the figure, the total charge is $750\ \mu\text{C}$ and the voltage across capacitor $C_2$ is $20\ \text{V}$. Then the charge on capacitor $C_2$ is:
Answer: (B) $590\ \mu\text{C}$
$C_2$ and $C_3$ are in parallel, so $C_3$ also has $20$ V across it: $q_3 = 8\times20 = 160\ \mu\text{C}$.
The total charge $750\ \mu\text{C}$ (the charge on $C_1$) is shared by $C_2$ and $C_3$: $q_2 = 750 - 160 = 590\ \mu\text{C}$.
Solution by Sreeraj P, M.Sc Physics