Q 12-02-095JEE MainJEE Main 2023 (10 Apr, Shift 2)Easy
The distance between two plates of a capacitor is $d$ and its capacitance is $C_1$, when air is the medium between the plates. If a metal sheet of thickness $\dfrac{2d}{3}$ and of the same area as plate is introduced between the plates, the capacitance of the capacitor becomes $C_2$. The ratio $\dfrac{C_2}{C_1}$ is
Answer: (A) $3:1$
A metal sheet of thickness $t$ reduces the effective gap to $d-t=\dfrac d3$, so $C_2=3C_1$.
Solution by Sreeraj P, M.Sc Physics