Q 12-08-194JEE MainJEE Main 2019 (10 Jan, Shift 1)Easy
If the magnetic field of a plane electromagnetic wave is given by $B = 100\times10^{-6}\sin\left[2\pi\times2\times10^{15}\left(t - \dfrac xc\right)\right]$, then the maximum electric field associated with it is: (speed of light $= 3\times10^8\ \text{m/s}$)
Answer: (A) $3\times10^4\ \text{N C}^{-1}$
$$E_0 = cB_0 = 3\times10^8\times100\times10^{-6} = 3\times10^4\ \text{N C}^{-1}$$
Solution by Sreeraj P, M.Sc Physics