Q 12-08-164JEE MainJEE Main 2021 (26 Feb, Shift 1)Easy
The maximum and minimum amplitude of an amplitude modulated wave is $16$ V and $8$ V respectively. The modulation index for this amplitude modulated wave is $x\times10^{-2}$. The value of $x$ is ______. (Round off your answer to the nearest integer)
Numerical value type. Enter your answer.
Answer: 33
$$\mu = \frac{A_{max} - A_{min}}{A_{max} + A_{min}} = \frac{16 - 8}{16 + 8} = \frac{1}{3} = 0.333 \approx 33\times10^{-2}$$
Solution by Sreeraj P, M.Sc Physics