Q 12-08-051JEE MainJEE Main 2024 (1 Feb, Shift 2)Easy
If the frequency of an electromagnetic wave is $60\ \text{MHz}$ and it travels in air along the $z$ direction, then the corresponding electric and magnetic field vectors will be mutually perpendicular to each other and the wavelength of the wave in m is
Answer: (C) $5$
$$\lambda = \frac{c}{f} = \frac{3\times10^8}{60\times10^6} = 5\ \text{m}$$
Solution by Sreeraj P, M.Sc Physics