Q 12-08-044JEE MainJEE Main 2025 (23 Jan, Shift 2)Easy
A time varying potential difference is applied between the plates of a parallel plate capacitor of capacitance $2.5\ \mu\text{F}$. The dielectric constant of the medium between the capacitor plates is 1. It produces an instantaneous displacement current of $0.25\ \text{mA}$ in the intervening space between the capacitor plates. The magnitude of the rate of change of the potential difference will be ______ $\text{V s}^{-1}$.
Numerical value type. Enter your answer.
Answer: 100
Displacement current $I_d = \epsilon_0\dfrac{d\phi_E}{dt} = C\dfrac{dV}{dt}$:
$$\frac{dV}{dt} = \frac{I_d}{C} = \frac{0.25\times10^{-3}}{2.5\times10^{-6}} = 100\ \text{V/s}$$
Solution by Sreeraj P, M.Sc Physics