Q 12-08-032JEE MainJEE Main 2026 (5 Apr, Shift 1)Easy
A displacement current of $4.0$ A can be set up in the space between two parallel plates of $6\,\mu\text{F}$ capacitor. The rate of change of potential difference across the plates of the capacitor is nearly $\alpha \times 10^6$ V/s. The value of $\alpha$ is ______.
Answer: (B) $0.67$
$I_d = C\dfrac{dV}{dt}$, so $\dfrac{dV}{dt} = \dfrac{4.0}{6 \times 10^{-6}} \approx 0.67 \times 10^6$ V/s.
Solution by Sreeraj P, M.Sc Physics