Q 12-08-013NEETJEE MainMedium
A parallel plate capacitor with plates of area $0.01\ \text{m}^2$ has the field between them changing at $10^{12}$ V m$^{-1}$ s$^{-1}$. The displacement current is ($\epsilon_0 = 8.85 \times 10^{-12}$ F/m)
Answer: (B) $0.0885$ A
$I_d = \epsilon_0A\dfrac{dE}{dt} = 8.85 \times 10^{-12} \times 0.01 \times 10^{12} = 0.0885$ A.
Solution by Sreeraj P, M.Sc Physics