Q 12-06-085JEE MainJEE Main 2023 (8 Apr, Shift 2)Easy
An emf of $0.08$ V is induced in a metal rod of length $10$ cm held normal to a uniform magnetic field of $0.4$ T, when it moves with a velocity of
Answer: (D) $2\ \text{m s}^{-1}$
$v=\dfrac{\varepsilon}{Bl}=\dfrac{0.08}{0.4\times0.1}=2\ \text{m s}^{-1}$.
Solution by Sreeraj P, M.Sc Physics